Question

integral of 4^3x dx

Answer 1

\[\text{The integraL of }4^{3 x}\text{ is }\frac{4^{3 x}}{3 \ln (4)}\text{}\]
\[\frac{4^{3 x}}{3 \ln (4)}+c\]

Answer 2

WOuld you by any chance explain it to me to understand better?

Answer 3

Let u=3x

dx=(du)/(3)
then, integrate..
(4^(u))/(3)/(ln(4))+C

((64)^(x))/(3)+C

Answer 4

\[\frac{d}{dx} b^x=b^x\ln(b)\] work backwards

Answer 5

e^y = 4
or y = ln 4

4^3x = e^(ln4)3x

Answer 6

\[\int b^xdx=\frac{b^x}{\ln(b)}\]

Answer 7

i guess it would be pretty much the same.

Answer 8

yeah, and (64)^(x)/(3lnx)+C

Answer 9

thank you