Question

Can someone clarify what happens to the negative sign when we have -(sqrt3/2)^2 + 1
I know it equals 1/2, but i'd like to know what happens to the negative sign. Thx

Answer 1

\[(-\sqrt{3/2} )^{2}+1\] ,is that the equation ????

Answer 2

yup Eyad

Answer 3

then cause of the power if the power is even so it delete the -ve sign ,while if its is odd i dont delete the power

Answer 4

\[-\sqrt{\frac{3}{2}}^2+1=-\frac{3}{2}+1=-\frac{1}{2}\] whereas
\[\left(-\sqrt{\frac{3}{2}}\right)^2+1=\frac{3}{2}+1=\frac{5}{2}\]

Answer 5

if u need more explanation ,tell me :)

Answer 6

Maybe i should of put the whole thing down, because it says: −(3√2)2+1=cos2x, cos x = 1/2. Sorry

Answer 7

I got -1/2 too, but i'd like to know what happens to make it positive?? thx

Answer 8

\[−(√3/2)^2+1=\cos2x\] cos 2x = 1/2

Answer 9

\[−(√3/2)^2+1=\cos2x\] cos x = 1/2