How do i convert (csc x) to (sec x) ?
would i have to go 1/sin x = csc x then use the sin^2x + cos^2x identity?
change it to cot=> change it to tan => change it to sec
is that the easiest way, experimentX?
wait wrong interpretation lol
ok :)
cscx \[\frac{1}{sinx}~~~~,~~~~tanx=\frac{sinx}{cosx}\] \[\frac{1}{tanxcosx}\] \[cotxsecx\]
thanks a lot, so changing it to 1 over tanxcosx will = the sec of x?
my example is: csc = 2 sqrt3 /3, sec = ?
\[\frac{1}{(tanx)(cosx)}=\frac{cotx}{cosx}=cotx(secx)\]
Ok thanks a lot Sam, is it cool if i try to work it out and post it and you check it later to see if i did it right?
\[cscx = 2 \sqrt3 /3\] \[\frac{1}{sinx}=\frac{2\sqrt3}{3}\] \[sinx=\frac{3}{2\sqrt3}\] \[sinx=\frac{\sqrt3}{2}\] \[x=60,120\] ----------------------------------- \[secx\] \[\frac{1}{cosx}\] \[\frac{1}{\cos60}~~~and~~~\frac{1}{\cos120}\] \[2~~~and~~~-2\]
Thank you mate, really appreciate your time and patience.
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