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Mathematics 18 Online
OpenStudy (anonymous):

How do i convert (csc x) to (sec x) ?

OpenStudy (anonymous):

would i have to go 1/sin x = csc x then use the sin^2x + cos^2x identity?

OpenStudy (experimentx):

change it to cot=> change it to tan => change it to sec

OpenStudy (anonymous):

is that the easiest way, experimentX?

sam (.sam.):

wait wrong interpretation lol

OpenStudy (anonymous):

ok :)

sam (.sam.):

cscx \[\frac{1}{sinx}~~~~,~~~~tanx=\frac{sinx}{cosx}\] \[\frac{1}{tanxcosx}\] \[cotxsecx\]

OpenStudy (anonymous):

thanks a lot, so changing it to 1 over tanxcosx will = the sec of x?

OpenStudy (anonymous):

my example is: csc = 2 sqrt3 /3, sec = ?

sam (.sam.):

\[\frac{1}{(tanx)(cosx)}=\frac{cotx}{cosx}=cotx(secx)\]

OpenStudy (anonymous):

Ok thanks a lot Sam, is it cool if i try to work it out and post it and you check it later to see if i did it right?

sam (.sam.):

\[cscx = 2 \sqrt3 /3\] \[\frac{1}{sinx}=\frac{2\sqrt3}{3}\] \[sinx=\frac{3}{2\sqrt3}\] \[sinx=\frac{\sqrt3}{2}\] \[x=60,120\] ----------------------------------- \[secx\] \[\frac{1}{cosx}\] \[\frac{1}{\cos60}~~~and~~~\frac{1}{\cos120}\] \[2~~~and~~~-2\]

OpenStudy (anonymous):

Thank you mate, really appreciate your time and patience.

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