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Let f(x)=x^2x Use logarithmic differentiation to determine the derivative ƒ'(x) ?
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lake log on both sides, log y = 2x log x use implicit differentiation your answer will be (2logx+2)x^2x
THANKS A LOT! GNITE!!
DO I HAVE TO TAKE THE DERIVative also?
yes ,,, dy/dx*1/y = (2logx+2) or dy/dx = y (2logx+2) y = x^2x or dy/dx = x^2x(2logx+2)
hmmm
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x^2 x (2 log(x)+2) ??
x^( 2x) * (2 log(x)+2)
thanks!!
there is a formula for such types of differentiation also,it goes as d/dx(u^v)= u^v*d/dx(v*log u) apply it here and see what you get???
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