Question

A projectile has maximum range 200m. What is the max height attained by it?

Answer 1

Do you have the formulas for range and height?

Answer 2

is the answer 50?

Answer 3

Are you simply checking it?

Answer 4

yep

Answer 5

?

Answer 6

Would you care to show your working?

Answer 7

ok
max range=v^2/g=200m
therefore v=sqrt(2000)
subs in eq for max height
(vsin$)^2/2g for $=45 degree g =10m/s^2
i get
max height 50m
is it correct?

Answer 8

Yep, correct.
Therefore, to conclude, for an ideal projectile motion, \[R\max = 4 H\]

Answer 9

thanks

Answer 10

and thats Hmax.

Answer 11

noted