hey guyz dis question is only for who appeared iit 2012
sq root 1+x^3
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
|dw:1334072939714:dw|
OpenStudy (anonymous):
aad r u der???
OpenStudy (anonymous):
did you???
OpenStudy (anonymous):
Square both sides.
OpenStudy (anonymous):
So, x^3 + 1 = 0
Or, (x+1) (x^2 - x+ 1) = 0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So, x = -1
OpenStudy (anonymous):
@sheena101 , @annas , is my answer correct?
OpenStudy (apoorvk):
this is an integration right??
OpenStudy (anonymous):
But can I not solve by general method? Can anyone explain this?
OpenStudy (apoorvk):
aah.. no. integration is not that.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Okay.
OpenStudy (anonymous):
who all appeared for IIT 2012???
OpenStudy (anonymous):
aad what r u doing?
OpenStudy (aravindg):
its very easy i didnt appear but i can help
OpenStudy (anonymous):
hahah ok ...u can try
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
G r u trying?????
OpenStudy (anonymous):
apoorvk tr u der??????????
OpenStudy (apoorvk):
\[\int\limits_{}^{} (t^{-4/3} + t^{-1/3})^{1/2}.dt\]
expand the term using binomial expansion for fractional expressions. and then integrate.
earlier problem about that x^2/(1+x^5) mein bhi last step mein wahi hoga