Question

In choosing a gaussian surface for a solid sphere you choose a spherical chell around the sphere because E is same at all points on it.But why is it so?i mean it is not like a hollow sphere where all points are equidistant.In a solid sphere each point is at a different distance from each point of the gaussian surface

Answer 1

could you please add a picture ... i usually misinterpret sentences??

Answer 2

Electric field is not the same at both these points.

Answer 3

you mean at r1 and r2 ??

Answer 4

Yep the outer spherical shell is what we use as a gaussian surface right?E is not same at all points on it

Answer 5

of course E is a vector field.

Answer 6

I meant the magnitude.Remember in Gauss law you choose gaussian surfaces such that E comes out of the integral

Answer 7

yes,i know i kinda remember that.

Answer 8

So here magnitude of E is not the same right on the gaussian surface because the points are not equidistant

Answer 9

usually the charge in solid sphere behave as it comes from a single point (it is because the these forces and field are vector component and the form the net resultant) ... so we choose Gaussian surface in such a way that it is symmetric ... so it will be equal.

Answer 10

Ok Ill think of it.I don't know why I am getting so confused

Answer 11

you know electric dipole??

Answer 12

Yes

Answer 13

it produces same effect as single charge

Answer 14

Show me how to think of a charge distribution.Visualising point charges is quite easy.But when it gets to charge distributions I am having trouble picturing it

Answer 15

I mean electric dipole is two charges, but it is equivalent to putting a single charge at some point.

Answer 16

If there's a spherical charged ball, then the top charges repel to bottom forward, and bottom charges repel to up forward, but at the end it moves forward, the up and bottom components cancel out each other.

Answer 17

Yeah

Answer 18

instead of that, it's equivalent to putting all charges on single point.