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The derivative of 8^x+8*7^x why do u get ln8+8x...
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8^x*
most likely it is a consequence of way it is worked out ....
yousually there is a ln(y=b^x) thing going on to ease the process
So anything raised to the x would be like this 6*ln(6)
almost, but sure
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y = a^x where 'a' is be any constant dy/dx = ln(a) a^x
best done using implicit differentiation let y = a^x taking log both sides. ln(y) = x ln(a) 1/y dy/dx = ln(a) => dy/dx = y ln(a) => a^x ln(a)
the other way is to change a to e let a = e^u ln(a) = u ln(e) = u therefore we have y = e^(ln(a)x) => use chain rule here, you will get the same result.
*** a = e^ln(a)
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