Question

An urn contains 8 white, 6 blue, and 9 red balls. How many ways can 6 balls be selected to meet each condition?
A) Three balls are blue, 2 are white, and 1 is red.
B) Two are blue, and 4 are red.

Answer 1

use random variables

Answer 2

http://mathforum.org/library/drmath/view/69151.html

Answer 3

paging @satellite73

Answer 4

lol, the other site thing is confusing..

Answer 5

hold on one second

Answer 6

ok 3 blue 2 white 1 red
\[\dbinom{6}{3}\dbinom{8}{2}\dbinom{9}{1}\] is it clear how to compute these?

Answer 7

Yes. Now?

Answer 8

Wait..so you just divide then multiply? Which results in 72?