An urn contains 8 white, 6 blue, and 9 red balls. How many ways can 6 balls be selected to meet each condition?
A) Three balls are blue, 2 are white, and 1 is red.
B) Two are blue, and 4 are red.

Question

An urn contains 8 white, 6 blue, and 9 red balls. How many ways can 6 balls be selected to meet each condition?
A) Three balls are blue, 2 are white, and 1 is red.
B)  Two are blue, and 4 are red.

anonymous · Answer

use random variables

anonymous · Answer

http://mathforum.org/library/drmath/view/69151.html

anonymous · Answer

paging @satellite73

anonymous · Answer

lol, the other site thing is confusing..

anonymous · Answer

hold on one second

anonymous · Answer

ok 3 blue 2 white 1 red 
$$\dbinom{6}{3}\dbinom{8}{2}\dbinom{9}{1}$$ is it clear how to compute these?

anonymous · Answer

Yes. Now?

anonymous · Answer

Wait..so you just divide then multiply? Which results in 72?