Question

Help me simplify this.

8x^2+4x+2/1-8^2

Answer 1

That can't really be simplified to nicely.

Answer 2

\[\frac{8x^2+4x+2}{1-8^2}=\frac{9x^2+4x+2}{-63}\]

Answer 3

Whoops. 8x^2 in numerator.

Answer 4

use this formula to factor the denominator A^3-B^3=(A-B)(A^2+AB+B^2)

Answer 5

it's 8X^3 not 8x^ cubed not squared

Answer 6

why don't you just start over and post the problem correctly?

Answer 7

I only noticed it when you typed it sorry

Answer 8

It's just cubed for the denominator, the numerator is squred

Answer 9

\[\frac{8x^2+4x+2}{1-8x^3}\]

Answer 10

Is that the correct problem?

Answer 11

yes, it is the correct proble. Can you do it?

Answer 12

\[\frac{8x^2+4x+2}{1-8x^3}=\frac{2(4x^2+2x+1)}{(1-2x)(1+2x+4x^2)}=\frac{2}{1-2x}\]

Answer 13

yur a genius! u get a medal! thanhank u :)

Answer 14

yw.

Answer 15

what does yw mean?

Answer 16

You're welcome

Answer 17

oh :)