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why is it -x/2 and not -3x/2
\[f=xe^{\frac{-x}{2}}\] \[f'=(x)'(e^{\frac{-x}{2}})+x(e^{-\frac{x}{2}})'\]
\[f'=1 \cdot e^{-\frac{x}{2}}+x (\frac{-x}{2})'e^{-\frac{x}{2}}\]
its not power rule, its e^u, of which derivative is u'*e^u
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