Question

Can you help me

Answer 1

start with a?

Answer 2

ok, when proving identities, start with the more complicated side then simplify to get to the other expression.... which side is more complicated to you?

Answer 3

try to put them in sine and cos only

Answer 4

ok.. do what @mathg8 , said...

Answer 5

ok so first, LHS, = 1/cos + sintheta/costheta

Answer 6

well ...that one is done ! :)

Answer 7

yep..

Answer 8

in #1
1/cos = secant

1 + sin/cos = 1/cos + sin/cos
no need to go to terms of sin or cos in this one

Answer 9

b

Answer 10

#2 i would foil LHS, use double angle on RHS

Answer 11

so is RHS, sin theta /costheta = tantheta

Answer 12

wait, i need to solve both sides

Answer 13

LHS and RHS

Answer 14

you don't have to

Answer 15

yeah i guess so

Answer 16

Oh. Ok I thought I needed

Answer 17

So for b how do I do it?

Answer 18

FOIL out the left, then use sin^2 + cos^2 = 1 to make them equal

Answer 19

see my attachment

Answer 20

that attachment is for b:)

Answer 21

Your task is to verify the identities given. Generally, look for ways in which you can manipulate a term into a different term, trying to get all of the terms to use the same trig ratio. Converting to sines and cosines is a LAST RESORT when other things dont work.

for a) convert tan to sin/cos, then you can add and get the right side
for b) FOIL out the terms then convet sin^2 + cos^2 to 1 and you get the right side
etc etc

Answer 22

ok, How do I do d?

Answer 23

last one

Answer 24

Thank you so much @mathg8

Answer 25

I really appreciate it

Answer 26

np ... have a paper with identity formulas and most of the time reduce everything to sin and cos