Question

If f(x)=(e^(2x)+1)^1/2 then f'(0)=

Answer 1

1

Answer 2

1/2 (e^(2x)+1)^-1/2 (e^(2x) ) (2)

so 1/2 and 2 gets cancelled...

(e^2x)/(e^2x + 1)

substitute 0...

e^0/(e^0 +1)
1/(1+1)

1/2

Answer 3

really? i got