Find the measure of angle P in the triangle below
this is the triangle i need to figure out
Do you know how to use cos and sin?
kind of im beginning on it. most problems, no i have no clue they have t be extremely short and simple
It is a right triangle.
meaning.....?
cos p = opposite/ hypotnus
Meaning you can use the law of sin for right triangle. Specifically Sin P =48/60
thats it? 48/60?
cos p = 48/60
Yes for sin for Cos use 36/60
thank you
Maybe I have it backwards.
Sin P = opposite side (48) / hypotenuse (60)
Did you get 53.13 degrees?
Even though it is not indicated a right triangle, it is because:\[48^{2}+36^{2}=60^{2}\]
I'm actually stuck on the same problem, what do you do with P? In other words, how'd you get 53.13?
I would first solve for the Sin of P Which is equal to One of the sides divided by the hypotenuse (it is a right triangle) Let me check my notes as there was some debate whether to solve for cosine vs sine. Be back in a minute.
Okay no worries! The subject is focused on Law of Cosines so I would assume to use Cosine.
It is sine theta it is equal to opposite side divided by the hypotenuse or for this triangle is 48/60 or giving it a value of 0.8 Now take the inverse sin of 0.8 to get the measure of the angle.
Ohh okay; understood! Thank you so much!
Actually one more thing... how would you find angle Q?
Did you get 53.13 degrees for angle P? Better yet is that one of your answer options?
It's an open answer so I'm not given choices.
Yes I did!
Angle Q is the right angle (90 degrees) and there are several methods to use. One easy way is to sa y, Sin Q = 60/60 = 1, and inverse sin 1 = 90 degrees, but to be sure do this:
To do..?
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