In order for cos(x) = sin(x + h), h must be equal to: Is it 120, 60, 45, or 90?
I know its one of those values
\[\sin (\theta + 90)= \cos (\theta)\]
f(x) is translated by vector\[\left| a \\ 0 \right|\] then it becomes f(x-a) since sin(x) is a translation of cos(x) by the vector where a= -90 we get the above answer
or think about it like this we know that cos(x) = cos(-x) and we know that sin(90-x) = cos(x) from this triangle |dw:1334347163876:dw| so sin(90-x) = cos(x) = cos(-x) now let -x = y and we have cos(y) = sin(90 + y)
\[\cos x=\sin (90-x)\] or \[ \cos x= \sin (90+x)\] here we have \[ \cos x= \sin (x+h)\] so here h= 90
Thanks a lot guys:). I have to submit my assignment in 25 minutes. You guys saved my life!
:D no problem happy to be of assistance
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