Question

@eigenschmeigen

Answer 1

@eigenschmeigen can you help me here please? I have 5 minutes left. im so dead

Answer 2

hey :D

Answer 3

yeah quick ask away!

Answer 4

Ok, we are doing the multiple choice section of my hw, which is the part I always get wrong. so here are the questions: (Btw, I will medal you for every answer via othe questions)

1.Given a = 31.5, b = 51.8, A = 33°. The value of c in triangle ABC is

57

29

57 and 29

no solution

Answer 5

And, If you dont mind, can you teach me some of this stuff after i submit the hw?

Answer 6

sure

Answer 7

Are you there?

Answer 8

yeah im trying to find my calculator xD

Answer 9

Oh lol ok:)

Answer 10

im gonna say 57, do you have time for me to check my working?

Answer 11

Sure. I have like little bit less than 10 mins

Answer 12

@TuringTest help us out? there's a time constraint

Answer 13

ok, its ok, no time for that:) new question

Answer 14

In a triangle ABC, b = 52 cm, a = 63 cm, and B = 41°. Determine the length of c.

only 79.1 cm

79.1 cm and 16.0 cm

only 16.0 cm

81.5 cm

Answer 15

http://ostermiller.org/calc/triangle.html

Answer 16

that will be quicker than me

Answer 17

http://nayuki.eigenstate.org/page/triangle-solver-javascript

Answer 18

i think the second link is better

Answer 19

Can you help me with this one?

Answer 20

i can derive it for you after

Answer 21

remember with these triangles, C is opposite c , A is opposite a etc

Answer 22

That would be great

Answer 23

wait! its not B!

Answer 24

its C

Answer 25

crap really sorry i misread

Answer 26

Kae:0 How about this one?

Answer 27

i am really sorry, did you have a chance to change it?

Answer 28

Yes :) its in microsoft word so its ok:)

Answer 29

Can you ee my new attachment?

Answer 30

Are you there?

Answer 31

A

Answer 32

sorry for my sluggish responses, i just got back from work and im a little tired

Answer 33

Omg, Im sorry to place a burden upon you. :(

Answer 34

haha its no problem

Answer 35

i enjoy maths so its ok

Answer 36

keep the questions coming!

Answer 37

hahha. Thank you:)

Answer 38

did you see my new attachment?

Answer 39

the answer to the last one was 1 + sinxcosx

Answer 40

No, I mean the new attachment I jsut put

Answer 41

39.3

Answer 42

Btw, Im going to give you about 60 medals

Answer 43

Oh no, 3 minutes left

Answer 44

Are you therE?

Answer 45

I have to submit in 1 minute:( last question

Answer 46

Hey! Are you there???

Answer 47

hey im doing it!

Answer 48

Oh sorry, I thought you left

Answer 49

its one of the last two, gimme a sec ill narrow down

Answer 50

kae:)

Answer 51

its C

Answer 52

the third one

Answer 53

OMG! IM done!

Answer 54

First of all, Im gonig to fan you:)

Answer 55

phew i was feeling the pressure there for a sec xD

Answer 56

You LITERALLY SAVED MY LIFE!

Answer 57

whats your name?

Answer 58

my name's jacob whats yours?

Answer 59

Sunny.

Thank you so much for your help Jacob. I really appreciate it.
Are you ready to level up like crazy?

Answer 60

I owe you BIG time.

Answer 61

haha its really no problem man im just happy i could be a help

Answer 62

Ready to level up?

Answer 63

did we get them right?

Answer 64

Im not sure, if we got them right yet, i just submitted my hw. i will know by tomorrow

Answer 65

Ready to level up jacob?

Answer 66

thanks for all those medals :D

ill start explaning some now

Answer 67

btw, that triangle solvver website, I didnt even know that existed. That was soooo helpful

Answer 68

to "solve" a triangle we are usually given 3 bits of information
here is a triangle:


the two rules we need to know and apply are:
1. The sine rule

\[\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinB} = 2R\]

(the 2R is used if the triangle is "inscribed" within a circle, and is the radius of the circle. i havent seen many questions where this is the case)

an example where this is appropriate:

there is also an "ambiguous case"
see here: http://en.wikipedia.org/wiki/Law_of_sines#The_ambiguous_case
its with practice you'll learn when to apply each rule

2. the cosine rule

this is really an extension of pythagoras to non right-angled triangles:

\[a^2 = b^2 + c^2 - 2bccosA\]
usually we need to know Side Angle Side (some abbreviate this to SAS)
to apply cosine rule

an example where cosine rule is appropriate :



sometime you will also need to use the fact that the angles within a triangle add up to 180 degrees .