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Mathematics 18 Online
OpenStudy (callisto):

A cute question - Coordinate geometry

OpenStudy (callisto):

Hmm.. I'm doing this now

OpenStudy (anonymous):

that's not cute,looks fearsome, jokin...

OpenStudy (callisto):

If there is a cute solution, then this would be a cute question :)

OpenStudy (anonymous):

is BG perpendicular to AC???

OpenStudy (anonymous):

if it is, then i think i may have something...

OpenStudy (mani_jha):

(a)(i) can be done by simply stating: AngleBAG=AngleBDG AngleABG=AngleGBD(Incentre is the point of intersection of angle bisectors, so BI bisects angle ABD)

OpenStudy (anonymous):

if I is an incenter that means BG is an angle bisector...

OpenStudy (mani_jha):

@Sarkar, I don't think so. Looks can be deceiving!

OpenStudy (anonymous):

that's my line...

OpenStudy (anonymous):

so SAS , they're congruent.

OpenStudy (mani_jha):

This is not a drama! Is my solution clear?

OpenStudy (anonymous):

crystal

OpenStudy (anonymous):

exactly @dpalnc

OpenStudy (anonymous):

So obiviouly Bg is perpendicular to aG.

OpenStudy (callisto):

@dpaInc lol My workings for ai: In ΔABG and Δ DBG ∠ABG = ∠ DBC (How should I write the reason?) BA = BD ( given) ∠BAG = ∠BDG (base ∠, isosΔ) ∴ ΔABG (is congruent to) Δ DBG

OpenStudy (anonymous):

*AC

OpenStudy (anonymous):

Triangle AI ANd Triangle ABE Angle ABE = Angle AGI Angle BAI = IAG => SImilar triangles Proves b

OpenStudy (anonymous):

"ABG = ∠ DBC (How should I write the reason?)" i think you mean angle DBG?

OpenStudy (callisto):

Sorry.. yup...

OpenStudy (anonymous):

BG is an angle bisector since BG goes thru the incenter I

OpenStudy (callisto):

Yup.. But how should I present it? Should it be like this? since BG goes through the incenter of the triangle, BG is the angle bisector, that is ∠ ABG = ∠ DBG In ΔABG and Δ DBG ∠ABG = ∠ DBG (proved) BA = BD ( given) ∠BAG = ∠BDG (base ∠, isosΔ) ∴ ΔABG (is congruent to) Δ DBG

OpenStudy (anonymous):

^^ Seems excellent presentation.

OpenStudy (anonymous):

i see you're using ASA. that looks fine too.

OpenStudy (callisto):

Oh... I forgot to write ASA ... sorry

OpenStudy (callisto):

@dpaInc another one is AAS, where S is BG=BG ?

OpenStudy (callisto):

Hmm.. G= (-7,0) ?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

Simple midpoint.

OpenStudy (anonymous):

Ad Equation of Circle: \[(x+7)^2 + (y - 9)^2 = 405\]

OpenStudy (callisto):

I= (-7, 9)?

OpenStudy (anonymous):

Yep.

OpenStudy (anonymous):

Radii = 9sqrt(5)

OpenStudy (callisto):

Good. I got them all. This one is not a cute one :(

OpenStudy (anonymous):

Haha. It's easy. Justl mixed jumbled up to confuse you. Real Charmer.

OpenStudy (callisto):

The key word is incentre... This troubles me :( I'm not familiar with the centres in a circle

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