Question

could i please have some help on the following attachment :) the last question, but you may need the information from the first questions :)

Answer 1

couldnt you just upload it straight???

Answer 2

what do you mean?

Answer 3

upload the question vertically so the reader doesnt have to twist his neck...

Answer 4

im sorry, but would you have written all of that up?

Answer 5

Would you mind turning the file you've upload 90 degree anti-clockwise? I would really appreciate your help. Thanks

Answer 6

yeah, you might not be able to see it very well though

Answer 7

just the last question please :)

Answer 8

Are you sure? 'cause I see that was wrong already...

Answer 9

I meant the first part

Answer 10

but in the mark scheme it says thats the answer :/

Answer 11

The answers you've written on the dotted line are correct. but not the working

Answer 12

oh right, okay, could you help me with them all please? :) sorry

Answer 13

and I think you've missed out some data . You've got some data for the volume, right? We need that data

Answer 14

* that -> those

Answer 15

thats all there is on the question paper :/

Answer 16

for ci
no of mole = 25.0/1000 x 0.100 = 0.0025 mole

Answer 17

Can you also give me the part a and part b?

Answer 18

Because in ciii, it mentioned that 'use the titre in titrations 2 and 3'

Answer 19

yeah hang on

Answer 20

oh yeah i see what you mean

Answer 21

so it is then 0.0025/20?

Answer 22

you meant ci?

Answer 23

for ci
no of mole = 25.0/1000 x 0.100 = 0.0025 mole

Answer 24

yeah, i have that

Answer 25

i need ciii

Answer 26

average volume = (20.1+19.9)/2 = 20.0cm^3 = 0.02 dm^3
concentration of HNO3 = no of mole / vol.
= 0.0025 / 0.02
= 0.125 M

Answer 27

yeah, thank you very much! :) sorry for the trouble

Answer 28

welcome. When you do calculations, make sure the unit is correct