Find the length of side of an equilateral triangle with area 10.2m^2???
the length is already given ..what do you have to find?
typo, excuse me.
Okay \[\text{Area of equilateral \triangle }= side^2 \times \frac{\sqrt{3}}{4}\]
Here Area is given and let the side be x now solve for x
sorry, can we back up for a a minute.
What happened to 1/2 b*h??
1/2 * b* h is the area of a Right triangle (one of the angle is \(90^o\) )
|dw:1334433951410:dw|
do I need to do something like that?
No ,you don't need a figure to solve this, particular, problem.
Here Area=10.2 \(m^2\) Formula:\[\text{Area of equilateral \triangle }= side^2 \times \frac{\sqrt{3}}{4}\] let the length of the side be \(x\) m \[\large 10.2 = x^2 \times \frac{\sqrt{3}}{4}\]
Understood this ?
yes.
thanks.
You're Welcome :) Hope you can do the rest !!
ok ?
can you make the calcule ?
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