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integrate: 4/((1-x)(1+x)^2)
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\[\int\limits_{}^{} 4/(1-x)(1+x)^{2}\]
make partial fractions.
oh yeah!thank you! i never think of partial fraction :/ i'll work on it now
can i take the constant out?
\[4\int\limits_{}^{}1/(1-x)(x+1)^{2}\]
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http://tutorial.math.lamar.edu/Classes/CalcII/PartialFractions_files/eq0009M.gif
thanks :)
i found A=1 but got nothing for B and C
i used linear system by say x=1, x=-1 and x=0
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Find A B and C \[ \frac{4}{((1-x)(1+x)^2)}\ = \frac{A}{(1-x)} + \frac{B}{(1+x)} + \frac{C}{(1+x)^2} \]
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