you roll a fair dice twice. find the probability at least one dice shows a 4 given that the minimum of the two numbers is a 3.
make a chart is what i do
1 2 3 4 5 6 1 2 3 4 5 6 mark all those that are 3x 1 2 3 4 5 6 1 2 3 x x x x 4 x 5 x 6 x
out of 7 ways; ony 2 have a four in them
2/7 if i see it right :)
oh ok. thank you so much! so the probability is 2/7
thats my guess, im a bit rusty at these so i cant say fer sure; but i think that it good
i was trying to calculate using formulas but then i got mixed up. this table seems very reasonable and easy
using the sample space and p(a) and stuff
yeah, i never remember the formulas that well
i was trying to learn it using the formulas since my prof might want to see calculations on the test
i figure the size of the given is: 3,3 3,4 3,5 3,6 = 7 ways to get a 3 as lowest 4,3 5,3 6,3 and 2 of those gots a 4
i do that too :)
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