Can someone who really likes math help me please?!
What do you need help with?
im not good at math but i can try
Ashley is designing a flag for a bicycling team. The line segments AB, CD, and EF are parallel to each other, as shown below. Which statement is true about the angles x and y? x = 70˚ and y = 110˚ because they are same-side interior angles x = 110˚ and y = 70˚ because they are corresponding angles x = 70˚ and y = 70˚ because they are alternate angles x = 70˚ and y = 20˚ because they are vertical angles
The 70 degree angle and x are corresponding angles. Therefore they are congruent. x and y are same side interior angles. Therefore they are supplementary.
Are B and D parallell?
B and D are points. Points are not parallel.
I meant the line segments. BA CD
A B C D which one?
If they are, the angle adjacent to y would also be 70 and y would be 20.
What do you think booboo?
c.. but im always wrong :(
If the 70 degree angle and x are congruent, what is x?
70?
problem with the question, these is a reason for each letter x = 70 corresponding angles y = 110 cointerior angles. but your options don't cover the correct answer
Yes. If x and y are supplementary, what is y?
110
?
Ok. Campbell screwed it up. He can help you now.
no. i think u were helping me.
If all those lines were parallel, the answer would be d.
?x = 70˚ and y = 110˚ because they are same-side interior angles??
or x = 110˚ and y = 70˚ because they are corresponding angles?
Try d.
well x and y are co interrior angles cuz the are in a 'C' like shape
Choose the first answer because x = 70 and y = 110.
And the reason is that they are same side interior angles.
x = 70˚ and y = 110˚ because they are same-side interior angles ------- Those two angles are formed by parallel lines CD and EF cut by the unlettered transversal
Can i get help with another graph one?
Ben uses a compass and a straightedge to construct , as shown. Which statement best explains why Ben uses the width HI to create the arc at J from point K? when EJ is constructed equal to HI. when JK is constructed equal to HI. Angle HIB is equal to angle JEK when . Angle BHI is equal to angle JKE when .
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