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OpenStudy (anonymous):
A new 13.3'' Macbook Pro costs $1,200.00, and a one year old 13.3'' Macbook Pro costs $1,000.00. How do I make an exponential decay model with this?
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OpenStudy (australopithecus):
Do you have the exponential decay formula I have forgotten it
OpenStudy (australopithecus):
I jsut need to see the formula I dont need to know what the variables mean
OpenStudy (anonymous):
I think it's y=a(1-r)t
OpenStudy (australopithecus):
Ugh deleted what I wrote.
D = Pe^(rt)
P =1200.00
D=1000.00
t = 1 year
r = ? (Rate)
solve for r
OpenStudy (australopithecus):
I assume you know how to use logirthms to solve this
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OpenStudy (australopithecus):
oops the equation is
D = Pe^(-rt)
OpenStudy (anonymous):
I forgot what that is.
OpenStudy (australopithecus):
ln(D/P) = ln(e^(-rt))
OpenStudy (australopithecus):
does that help?
OpenStudy (anonymous):
sorry but no it doesn't.
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OpenStudy (australopithecus):
Logrithmic rules
1) log_b(mn) = log_b(m) + logb(n)
2) log_b(m/n) = log_b(m) – logb(n)
3) log_b(m^(n)) = n · log_b(m)
4) log_3(3) = 1
5) log_e(x) = ln(x)
6) log(x) = y is the same as x =10^(y)
7) log_10(x) = log(x)
OpenStudy (australopithecus):
Does that help?
OpenStudy (australopithecus):
Log_3(x) =\[\log_3(x)\]
OpenStudy (anonymous):
Yes it does. Thanks.
OpenStudy (australopithecus):
if you want me to check your answer I can do that as well
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OpenStudy (anonymous):
no it's okay.
OpenStudy (australopithecus):
ok then back to the grind for me
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