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√ 3x − 2 = 4 − x
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The 3x -2 is all under the radical sign, I don't know if that changes much.
square both sides
do you know how ?
I believe so, let me try it out & I'll see if it's right.
than will get 3x-2=16-8x+x^2
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ok ?
why does the 8 have an x as well?
so do you know the formula is (a-b)^2 = a^2 -2ab +b^2
Okay now I'm totally lost. I had gotten 3x-2=16-x^2 Which I presumably need to factor. I had changed that into -x^2+3x+18=0, I thought all I needed now was to factor.
4-x squared not is 16-x^2 because there is (4-x) squared
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- both sides sign all terms toghether and not single,alon
4-x isn't in parentheses though.
\[(\sqrt{3x}+x)^{2}=6^{2}\]
solve!
I actually guessed & got it right. So thanks anyways.
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np..!!
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