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Mathematics 8 Online
OpenStudy (anonymous):

To use a school copier, a 4- digit code using the digits 0-9 must be entered. If each code cannot begin with the number 0 and there are 81 acceptable codes, what is the probability that someone will randomly select a usable code?

OpenStudy (anonymous):

\(\frac{1}{81}\)??

OpenStudy (anonymous):

how many four digit numbers are there?

OpenStudy (anonymous):

does not say

OpenStudy (anonymous):

number acceptable ---------------- will be the answer total number

OpenStudy (anonymous):

sure it does... use four digits, 0 to 9.... how many possible codes are there?

OpenStudy (anonymous):

i got one

OpenStudy (anonymous):

let's see... 0000 0001 0002 0003 0004 ... 9999 so there are how many possible codes?

OpenStudy (anonymous):

when u divide

OpenStudy (anonymous):

81/10,000

OpenStudy (anonymous):

that looks right to me

OpenStudy (anonymous):

probability questions usually boil down to number of good ways / number of all the ways

OpenStudy (anonymous):

thank you

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