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To use a school copier, a 4- digit code using the digits 0-9 must be entered. If each code cannot begin with the number 0 and there are 81 acceptable codes, what is the probability that someone will randomly select a usable code?
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\(\frac{1}{81}\)??
how many four digit numbers are there?
does not say
number acceptable ---------------- will be the answer total number
sure it does... use four digits, 0 to 9.... how many possible codes are there?
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i got one
let's see... 0000 0001 0002 0003 0004 ... 9999 so there are how many possible codes?
when u divide
81/10,000
that looks right to me
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probability questions usually boil down to number of good ways / number of all the ways
thank you
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