Question

Are my answers correct for this trigo question?

Answer 1

General form of the function: -2tan(3(x-(-pi/3)))+3
• Domain: {x | all real numbers except -30 degrees +60n}
• Range: {y | y is an element or R}
• Period: pi/b, where b = 3. Therefore, pi/3
• Vertical Asymptotes: -0.5 and 0.5. OR –pi/6 and pi/6.
• Zeroes: x = …, -1, 0, 1, 2, … (rounding off the values)
• Symmetry: Since tan(-x) = - tan(x) then tan (x) is an odd function and its graph is symmetric with respect the origin.
• Y-intercept: We set x = 0 so in this case -2tan(3(0-(-pi/3)))+3 = y = 3

Answer 2

Yes i'm pretty sure your right (:

Answer 3

@experimentx, Are all of these correct?

Answer 4

damn: wolfram is troubling me.

Answer 5

+60 is right.

Answer 6

Ok, so except for the domain, is everything else correct?

Answer 7

http://www.wolframalpha.com/input/?i=y+%3D+-2tan%283x+%2B+pi%29+%2B+3

+pi/6 + n (pi/3) where n is set of integer, this is your domain.

Answer 8

So are all the properties correct?

Answer 9

seems all right ... never thought of symmetricity about a point.

Answer 10

not sure about zeros
check using calculator.
http://www.wolframalpha.com/input/?i=solve+0+%3D+-2tan%283x+%2B+pi%29+%2B+3

Answer 11

Oo... found on error,
point of symmetricity is 0,3

Answer 12

what is symmetricity? mine is symmetry

Answer 13

the state of being symmectic is called symmetricity, your point of symmetry is 0. 3

Answer 14

Ohhh!

Answer 15

So my answer for symmetry is wrong?

Answer 16

What should I put?

Answer 17

my guess says 0, 3

Answer 18

Oh ok, everything else is good?

Answer 19

everything is all right, except zeros ... I am not sure, I don't have a calculator.

Answer 20

ok. Awesome. Thank you Experiment

Answer 21

welcome ... at least I learned a new thing. Usually I looked on lines as axis of symmetry.
From now on, I will also look on a point.