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Mathematics 15 Online
OpenStudy (anonymous):

How do you find the greatest common factor of x^(2)y^(4), xy^(6) Please explain step by step

OpenStudy (anonymous):

x^2y^12 is not the correct answer

OpenStudy (anonymous):

is the whole xy to the 6th? like (xy)^6 ?

OpenStudy (anonymous):

\[x ^{2}y ^{4}, xy ^{6}\] Thats the question, the answer to the problem is xy^4

OpenStudy (anonymous):

yep that is indeed correct xy^4 is the hcf because they both have the factor of xy^4.

OpenStudy (anonymous):

they both can only have one x and the highest y value is 4, hence xy^4.

OpenStudy (anonymous):

i dont underdstand how to get xy^4 can you show me the steps?

OpenStudy (anonymous):

Take the lowest exponent of x times the lowest exponent of y

OpenStudy (anonymous):

so x^2y^4, xy^6 right? Factors are numbers you multiply together to get another number. x^2y^4 factors> (x^2, y^4) xy^6 factors> (x, y^6) and remember it's "common factors" so they have to contained in both hence for x it is just x also known as x^1 and y is y^4.

OpenStudy (anonymous):

That's the best way I can explain it, I hope it helps.

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