please help explain this to me. solve for the x's by factoring x(3x+1)=2
I know I'm suppose to subtract the two to both side to make the equation equal zero but not sure whats next

Question

please help explain this to me. solve for the x's by factoring x(3x+1)=2 
I know I'm suppose to subtract the two to both side to make the equation equal zero but not sure whats next

kropot72 · Answer

Expand x(3x + 1) then subtract 2 from each side. Do you recognise what you then have?

anonymous · Answer

4x-1=0?

anonymous · Answer

never mind i see my mistake

anonymous · Answer

4X+X-2=0 ?

kropot72 · Answer

$$x(3x+1)=3x ^{2}+x$$

anonymous · Answer

huh I dont know why i keep going to 4x in stead of 3xsquared

anonymous · Answer

how did you do the little squared thinggy

kropot72 · Answer

I used the Equation button below the answer box.
$$3x \times x=3x ^{2}$$

anonymous · Answer

i see my mistake now, thank so much, i gave you a medal

kropot72 · Answer

You're welcome :).
You should reach the following:
$$3x ^{2}+x -2=0$$
Canyou factorise this to find the two solutions for x?

anonymous · Answer

yes 3x-2=0 is x=two thirds and x+1=0 is x=-1

kropot72 · Answer

Well done!!

anonymous · Answer

ok now can you help me with finding the square root of something.?

kropot72 · Answer

Yes.Bring it on!