Question

An airplane takes off at a 10° angle and travels at the rate of 350 ft/sec. Approximately how long does it take the airplane to reach an altitude of 25,000 feet? (Give the answer to two decimal places.)

Answer 1

The vertical component of the velocity of the airplane is 350 sin 10°. Thus, it takes 25000/(350 sin 10°) seconds or 411.34 seconds (approx. 6.86 minutes) to reach 25000 feet in altitude.

Answer 2

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