Question

cos 2θ = 11 sin θ − 5

Solve the given equation

Answer 1

I think I just have an issue with factoring it. This is all I have so far.

2sin^2theta +11sin theta - 6

Answer 2

That's right, I'm not sure how to easily find the factorisation here though.

Answer 3

(2sin(theta)-1)(sin(theta)+6) works, but I didn't come up with that myself.

Answer 4

So given that I just find where theta = 1/2?

Is it possible to find when theta = -6?

Answer 5

sin(theta) is between -1 and 1 so no that factor can't be zero and so you only have to look at the other one.

Answer 6

That might have been confusing: you are right. You just have to find the values of theta where sin(theta)=1/2.

Answer 7

Alright, I got it. Thanks again.