cos 2θ = 11 sin θ − 5

Solve the given equation

Question

cos 2θ = 11 sin θ − 5

Solve the given equation

anonymous · Answer

I think I just have an issue with factoring it. This is all I have so far.

2sin^2theta +11sin theta - 6

anonymous · Answer

That's right, I'm not sure how to easily find the factorisation here though.

anonymous · Answer

(2sin(theta)-1)(sin(theta)+6) works, but I didn't come up with that myself.

anonymous · Answer

So given that I just find where theta = 1/2?

Is it possible to find when theta = -6?

anonymous · Answer

sin(theta) is between -1 and 1 so no that factor can't be zero and so you only have to look at the other one.

anonymous · Answer

That might have been confusing: you are right. You just have to find the values of theta where sin(theta)=1/2.

anonymous · Answer

Alright, I got it. Thanks again.