a particle moves along a line so that, at time t, its position is s(t)=8sin2t. for what values of t does the particle change direction?
where \(\cos(2t)=0\) because that is where it goes from increasng to decreasing
okay which is pi/4
but how would i figure out the particles max velcoity? (Next part of the question)
that is one point, yes
velocity is given by \(16\cos(2t)\) as it is the derivative of the position. differentiate again to get the second derivative, that will tell you where the first derivative has a max
which is -32sin2t?
actually if it just says "what is the particles max velocity" you can reason that since \(-1\leq \cos(x)\leq 1\) you must have the maximimum velocity is 16
since that is the biggest \(16\cos(2t)\) can be
and how did u determine it is 16?
yes your second derivative is right
because the largest cosine can be is 1 so the largest 16cosine can be is 16
how would i show my work for that?
i would write that since \(-1\leq \cos(x)\leq 1\) you get \(-16\leq16\cos(2t)\leq 16\)
okay thanks
how would i determine the max distance from the origin for the function, s=4sin4t
Join our real-time social learning platform and learn together with your friends!