what is the max distance from the origin for the function s=4sin4t
why is it finite?
I think he's asking for the maxima :|
answer is 4
and the min distance is 0
i dont know how to get that...
min is -4, not 0
thats what the answer states, in the back of the book
Okay, first, you have to know that for the basic sine function, the maximum is 1 and the minimum is -1. Forget about the a value, so you have 4x -1 <= sin(4t) <= 1 You have to put the a value now, so multiply everybody by 4 (a's value) -4 <= sin(4t) <= 4 These are the Maximum and the minimum, and I don't know why your book says 0.. :/
Oops sorry Should be -4 >= sin(4t) >= 4
yes thats excatly how i thought about it.
Since in an inequality equation, when you multiply or divide, you have to flip the sign. Then I don't know, you can graph it if you want, and you'll find out that the minimum is not at 0.
ok
i think this is in polar form
^ That one works with the range of [0,4] :O
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