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a^2 - 10ab +3b^2 complete factoring... is this prime ? because I cannot solve it
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\[a^2-10ab+3b^2=0\]
quadratic formula is what you need
ok
Yes, it is prime.
\[-b \pm \sqrt{b^2-4ac}\over2a\]
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\[\pm\]
that just means either or will yield the same answer.
ok thanks
that will probably drive you insane though...be warned.
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Good luck with this one, I know it was fun for me :D
You can factor it over the real numbers as \[\left(a-\sqrt{22} b-5 b\right) \left(a+\sqrt{22} b-5 b\right) \] I think there asking you to factor it over the integers. It is prime over the integers.
Forget quadratic formula. That will probably be easier.
YEA IT WAS MY LAST PROBLEM I PUT PRIME FOR SOME REASON I COUULDNT FIGURE IT OUT srry caps lok
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