a^2 - 10ab +3b^2
complete factoring... is this prime ? because I cannot solve it

Question

a^2 - 10ab +3b^2 
complete factoring... is this prime ? because I cannot solve it

anonymous · Answer

$$a^2-10ab+3b^2=0$$

anonymous · Answer

quadratic formula is what you need

anonymous · Answer

ok

anonymous · Answer

Yes, it is prime.

anonymous · Answer

$$-b \pm \sqrt{b^2-4ac}\over2a$$

anonymous · Answer

$$\pm$$

anonymous · Answer

that just means either or will yield the same answer.

anonymous · Answer

ok thanks

anonymous · Answer

http://en.wikipedia.org/wiki/Quadratic_formula#Quadratic_formula

anonymous · Answer

that will probably drive you insane though...be warned.

anonymous · Answer

Good luck with this one, I know it was fun for me :D

anonymous · Answer

You can factor it over the real numbers as
$$\left(a-\sqrt{22} b-5 b\right)
   \left(a+\sqrt{22} b-5
   b\right)
$$
I think there asking you to factor it over the integers.
It is prime over the integers.

anonymous · Answer

Forget quadratic formula. That will probably be easier.

anonymous · Answer

YEA IT WAS MY LAST PROBLEM I PUT PRIME FOR SOME REASON I COUULDNT FIGURE IT OUT
srry caps lok