Question

solve by using quadratic form 2y squared-2y-1=0
the answer i got is way wrong, can anyone help me solve?

Answer 1

You want to do this using the quadratic formula?

Answer 2

thats what the book says to do

Answer 3

Ok, first you need to compute b^2-4ac

ay^2+by+c=0, so here a=2, b=-2 and c=-1

Answer 4

want me to show you what i have and you can tell me where i went wrong?

Answer 5

ok, that's fine too.

Answer 6

\[2y^2-2y-1=0\]
\[y=\frac{2\pm \sqrt{(-2)^2-4(2)(-1)}}{2(2)}=\frac{2\pm \sqrt{12}}{4}=\frac{2\pm2\sqrt{3}}{4}=\]
\[\frac{1}{2}\pm \frac{\sqrt{3}}{2}\]