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OpenStudy (anonymous):
Simplify (2sqrt5 + 3sqrt7)^2?? I keep getting different answers every-time I try to solve. What steps do I do??
14 years ago
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OpenStudy (zepp):
Show what you did?
14 years ago
OpenStudy (zepp):
Okay, since 2sqrt(5) and 3sqrt(7) are annoying, can you develop them so it would be only sqrt(#)?
14 years ago
OpenStudy (zepp):
E.g.: 2sqrt(5) could be expanded to sqrt(20)
14 years ago
OpenStudy (anonymous):
3sqrt(7) = 42?
14 years ago
OpenStudy (zepp):
Nope, 3 = sqrt(9)
sqrt(9)*sqrt(7) = sqrt(63)
14 years ago
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OpenStudy (zepp):
\[(\sqrt{20}+\sqrt{63})^2\]
14 years ago
OpenStudy (zepp):
Do something with it
Hint: \[(a+b)^2 = a^2+2ab+b^2\]
14 years ago
OpenStudy (anonymous):
So sqrt(20) is A?
14 years ago
OpenStudy (zepp):
Yes.
14 years ago
OpenStudy (anonymous):
{ sqrt(20) + sqrt(63)}^2 = sqrt(20)^2 + 2(20)(63) + (63)^2
14 years ago
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OpenStudy (zepp):
Uh, you forgot some sqrt somewhere
14 years ago
OpenStudy (anonymous):
{( 2sqrt(5) + 3sqrt(7)^2} = 83 + 12sqrt(35)
14 years ago
OpenStudy (zepp):
\[(\sqrt{20})^2+2(\sqrt{20}\sqrt{63})+(\sqrt{63})^2\]
14 years ago
OpenStudy (zepp):
So it would be 20 and 63 at both ends, since sqrt and ^2 cancels out
\[20 + 2\sqrt{20*63}+63\]
Answer should be pretty obvious now, simplify this and you'll get the answer.
14 years ago
OpenStudy (anonymous):
83 + 12 sqrt(35)
14 years ago
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OpenStudy (zepp):
wooot! :D
14 years ago
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