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OpenStudy (anonymous):
Math proof. Suppose that A\B are disjoint from C and x is in the element of A. Prove that if x is in the element of C then x is in the element of B.
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OpenStudy (zarkon):
where are you stuck?
OpenStudy (zarkon):
if x is in C what can you say about x's relationship with A\B?
OpenStudy (anonymous):
I'm stuck at the very beginning.. So I have my givens: x is not in (A\B n C) and x is in A. My goal: x is in C which implies that x is in B.
OpenStudy (anonymous):
Which I can further imply from my givens that x is not in B and x is not in C. Right?
OpenStudy (zarkon):
if x is in C then x is not in A\B so x is in (A\B)'
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OpenStudy (zarkon):
\[A\backslash B=A\cap B'\]
OpenStudy (zarkon):
so \[(A\backslash B)'=A'\cup B\]
OpenStudy (zarkon):
so \(x\in A\) and \(x\in A'\cup B\)
ie
\[x\in A\cap(A'\cup B)=A\cap B\subseteq B\]
OpenStudy (anonymous):
Does A' mean its not A?
OpenStudy (zarkon):
the complement of A
\[\overline{A},A',A^{c}\]
whatever notation you use.
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OpenStudy (anonymous):
HAH, okay gotcha.
OpenStudy (zarkon):
good :)
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