Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

Math proof. Suppose that A\B are disjoint from C and x is in the element of A. Prove that if x is in the element of C then x is in the element of B.

OpenStudy (zarkon):

where are you stuck?

OpenStudy (zarkon):

if x is in C what can you say about x's relationship with A\B?

OpenStudy (anonymous):

I'm stuck at the very beginning.. So I have my givens: x is not in (A\B n C) and x is in A. My goal: x is in C which implies that x is in B.

OpenStudy (anonymous):

Which I can further imply from my givens that x is not in B and x is not in C. Right?

OpenStudy (zarkon):

if x is in C then x is not in A\B so x is in (A\B)'

OpenStudy (zarkon):

\[A\backslash B=A\cap B'\]

OpenStudy (zarkon):

so \[(A\backslash B)'=A'\cup B\]

OpenStudy (zarkon):

so \(x\in A\) and \(x\in A'\cup B\) ie \[x\in A\cap(A'\cup B)=A\cap B\subseteq B\]

OpenStudy (anonymous):

Does A' mean its not A?

OpenStudy (zarkon):

the complement of A \[\overline{A},A',A^{c}\] whatever notation you use.

OpenStudy (anonymous):

HAH, okay gotcha.

OpenStudy (zarkon):

good :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!