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Use the Ratio Test to find the interval of convergence of SUM [(-3x)^n/3n+1 ]. I have -1/3
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your interval is a little off
What did you get??
\[\left(-\frac{1}{3},\frac{1}{3}\right]\]
\[-1/3<x\le 1/3\]
Ok ,s o how do you know that 1/3 is included??
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alternating series test
Wellllll........i did the AST to get those two answers. But should I plug those into the equation?
you need to plug -1/3 and 1/3 into the orignial sum for x and then test for convergence
oooooooooooh, im sorry. I understand. What I did was called the Ratio test. But now I need to use the AST.
you need to check the end points...with one of them (1/3) you can use the ast
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