Rectangle A has a length of 2x + 6 and a width of 3x. Rectangle B has a length of x + 2 and an area of 12 square units greater than Rectangle A’s area. What is a simplified expression for the width of Rectangle B?

x + 2
x + 1
6x + 6
6(x + 2)(x + 1)

Question

Rectangle A has a length of 2x + 6 and a width of 3x. Rectangle B has a length of x + 2 and an area of 12 square units greater than Rectangle A’s area. What is a simplified expression for the width of Rectangle B? 

x + 2
x + 1
6x + 6
6(x + 2)(x + 1)

campbell_st · Answer

area of rectangle A = (2x+6)(3x) = 6x^2 + 18x

Reatangle B is 12 units larger so the area is    6x^2 + 18x + 12 = (x +2)(6x+6)

reactangle B has an area of (x +2)(6x+6)

with length (x+2) then the width is (6x + 6)

experimentx · Answer

(2x+6)3x = 6x^2 + 18x
(x+2) (y) = 6x^2 + 18x + 12
(x+2) y = 6(x+1)(x+2)
y = 6(x+1)

anonymous · Answer

@experimentX is the bottom one the answer?

anonymous · Answer

i'm sorry i mean the second one

experimentx · Answer

yes ... sorry I lost connection suddenly.

anonymous · Answer

ok