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Simplify the following attached expressions.
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1.
2.
3.
1. \[(x-3)\div(x+4)\] Do you want me to take you thru the solution?
Well, can you solve the equations then show me how to do them?
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For problem 1 firstly you separately factorise the numerator and the denominator. Do you know how to do this?
Kinda yeah. But can you solve 2 & 3?
The answer to 2 is 10a/7. Please can you stay with me on problem 1.
Yeah. I'll stay with you. But can you solve 3 & then we can see how you did it?
The answer to 3 is:\[4\div(x+y)\]
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That's what I got(:
Good. What did you get for 1 and 2?
The numerator of problem 1 factorises as follows: \[x ^{2}-7x+12=(x-4)(x-3)\] Can you factorise the denominator?
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