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Mathematics 15 Online
OpenStudy (anonymous):

simplify the following expression: sin^2x/1+cosx

OpenStudy (anonymous):

i need help after i simplify it to \[1-\cos ^{2}x \div 1+\cos ^{2}x\]

OpenStudy (anonymous):

*1-cosx in denominator

OpenStudy (anonymous):

*1+cosx (sorry having typos)

OpenStudy (zepp):

You should try multiplying this by (1-cos(x))/(1-cos(x))

OpenStudy (anonymous):

do i multiply just in the denominator?

OpenStudy (zepp):

You have to do it in both, or the fraction wouldn't be equal as the one you wrote, um, I gotta go, will be back in 'bout 15 minutes, good luck ;)

OpenStudy (anonymous):

|dw:1334796121637:dw| this is where i get stuck

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