Use the Counting Principle to find the probability. choosing the 8 winning lottery numbers when the numbers are chosen at random from 0 to 9
10 choose 8?
that should be how many ways there are to choose 8 from 10; which would make the totality of the set; and there is only 1 way to choose the correct numbers in a specific order
wait, can the numbers be used more than once?
i spose it would be helpful if i actually knew the rules to playing a lottery
^^Hahaha True Well I Have A Multiple Choice Witch Are A: 1/10,000,000 B: 1/1,000,000,000 C: 1/100,000,00 D: 1/43,046,721
Those Are Fractions By The Way.
yeah, i think we can rule out the 2!/10!
10^8 is the under most likely
i think you missed a zero on C
Haha Yes I Did Sorry..
the probability of picking a correct number in any position is 1/10 10P8 1/10^8 aint an option so im gonna make my best guess as C :)
Haha! (: Okay Thanks! Dat Actually Really Helped! I Was So Confused On Dis Question (:
another way to look at it is: from 00000000 to 99999999 there are 100000000 different ways; and only 1 is right
OMG! I Get It Now! Dat Makes It Alot Easier! (((((:
lol
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