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Six runners are in a foot race. How many different ways can they come in 1st, 2nd, and 3rd place?
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You have 6 choices for first place, 5 for the second (one has already placed first) and 4 for third place. Thus, you have \[6\cdot5\cdot4=120\]ways.
Thank you! :)
You're welcome.
You can also write this as nPr (order matters) =n!/(n-r)! n=6 r=3 6!/3!=6*5*4
alright, thank you as well. :)
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If you don't understand that, it's ok, you'll learn later on. But if you do, I guess it works too ;)
I understand it alright, it's just some of them I don't haha. But yeah, I shall learn it later on!
:)
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