The first three terms of an arithmetic sequence are given by x, (2x -5), and 8.6.
What is the first term and the common difference?
Well the differnce is "common" for a reason. Set the difference equal, solve for x, and you have your answers.
a, b, c common diff = c-b or b-a
What is the reasoning for (2x - 5) - x = 8.6 - (2x - 5)
Why do we make them equal
FOO FOO STEAL MAH MEDAL
Because we know in an arithmeic series, that each term has the same difference as the preveious
It's actually by definition.
I understand that they equal, d is equal to d but why can't I just go 2x - 5 - x = the answer?
Because. That doesn't simplify to a constant.
Is it because you require an equation to solve the problem and not an expression?
Yes.
it's correct.
It's because you get two expressions, actually. Those two expressions are equal, but not equivalent.
But 2x - 5 - x would be x - 5 which is just an expression right? but we need an equation to solve the problem? I am trying to understand the philosophy behind how this works.
(in the sense that x+3+8 is equivalent to x+2+9)
if you think, a-b = b-c both will give you the same value.
Well. We actually get two expressions.
a-b = b-c, as foo foo said.
We do but the expressions equal eachother right?
yes.
we will get a value for 'x' then.
a-b is an expression, and b-c is also an expression. Each of these is the comon difference.
(2x - 5) - x = x - 5 you CAN'T make it equal to zero right?
Wat do you mean, equal zero?
No, not equal to zero
Like if you went 2x -5 - x = x -5 then took x - 5 = 0, x = 5
Because x-5 is the common difference.
not zero; the common diference
(2x - 5) - x = 8.6 - (2x - 5) x = 6.2
I see But making a quadratic equal 0 works because it when you make a quadratic equal to 0 it finds the x intercepts right?
We know a value x-5 is the common difference, and also a value 2x-5-x, which is also the common difference. We can set them equal because we know the represent the same value (the common difference)
Well, you set it equal to zero
because in a quadratic function y=ax^2+bx+c, you are looking for the x-value when y is equal to zero (in other words, the x intercept)
the point (x,0) is the x intercept.
Another question, adding a negative is the same as minusing a positive and minusing a postive is the same as adding a negative right?
There are two unknowns in a quadratic function.
Thanks
When we search for the x-intercept, we know that y=0, because the x intercept is on the x-axis and has no vertical height.
Another question, adding a negative is the same as minusing a positive and minusing a postive is the same as adding a negative right? - those are properties the directly follow from our definition of negative numbers and subtraction, as well as addition.
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