Question

Intergral (2(x^4)^1/2-x^-1/2)dx= ?

Answer 1

I have no idea what the actual function looks like based on what you posted...

Answer 2

[2(x^4)^(1/2)-x^(-1/2]*dx= ?

Answer 3

So rewrite it to something that makes it easier or more obvious for that matter to integrate.

Answer 4

\[\int\limits_{}^{}(2*(x ^{4})^{-1/2}-x ^{-1/2})dx\]
Is this it?

Answer 5

I think the first term has a positive 1/2 exponent as in x^4 is in a square root. Whether the two is as well, I don't know.

Answer 6

asker, why don't you just integrate it separately? i think what @kropot72 has is what you'ver written.

Answer 7

If I give a positive sign to the 1/2 of the first term the result of integration is:\[2/3*x ^{2}-2\sqrt{x}+C\]

Answer 8

If I give a negative sign to the 1/2 index of the first term the result of integration is:\[-(2/x)-2\sqrt{x}+C\]