Intergral (2(x^4)^1/2-x^-1/2)dx= ?

Question

anonymous · Answer

I have no idea what the actual function looks like based on what you posted...

anonymous · Answer

[2(x^4)^(1/2)-x^(-1/2]*dx= ?

anonymous · Answer

So rewrite it to something that makes it easier or more obvious for that matter to integrate.

kropot72 · Answer

$$\int\limits_{}^{}(2*(x ^{4})^{-1/2}-x ^{-1/2})dx$$
Is this it?

anonymous · Answer

I think the first term has a positive 1/2 exponent as in x^4 is in a square root. Whether the two is as well, I don't know.

anonymous · Answer

asker, why don't you just integrate it separately?  i think what @kropot72  has is what you'ver written.

kropot72 · Answer

If I give a positive sign to the 1/2 of the first term the result of integration is:$$2/3*x ^{2}-2\sqrt{x}+C$$

kropot72 · Answer

If I give a negative sign to the 1/2 index of the first term the result of integration is:$$-(2/x)-2\sqrt{x}+C$$