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Write the product as a sum. 13 sin (x/2) cos (x/4) The answer I keep getting is 1/2 (sin(3x/4)+sin(x/4)) Is this wrong? or can it be simplified further as 1/2sinx??
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@inkyvoyd
?
Sorry, I forget product-sum formulae as well @FoolForMath
@Callisto
The product sum formula is sinUcosV= 1/2(sin(U+V)+(sin(U-V)))
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\[1/2[\sin(x/2+x/4)+\sin(x/2-x/4)]\]
But the answer I get from that is incorrect??
\[1/2[\sin(3x/4)+\sin(x/4)]\]
You should multiply by 13
what about 13?
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ohhhhhhh so 13/2 should be in the front? wow I can't believe I missed that
The 13 that was in fron of the product in the question.
yes thank you.
With pleasure.
FYI: There is cool name of this formula: http://mathworld.wolfram.com/ProsthaphaeresisFormulas.html
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