Would the vertex of the quadratic equation y=4x^2+8x+1 be (-1,9)?
Use -b/(2a) to find it.
Well, yeah, I did that is my answer right? When I did that I got x= -1
-1 is correct. Now insert -1 in the equation to get the value for y.
I did but I feel like I got the y part wrong
You are correct. you should get -3. which is correct. So, this is NOT the vertex.
Would it be 3?
I mean -3 and thanks!
Correct.
What would the x intercepts be?
When x-intercept, y = 0 y=4x^2+8x+1 0=4x^2 + 8x + 1
then the next step is to subtract 1 from both sides right?
Nope, factor or use the quadratic formula.
oh.
So (2x ) (2x )
yes..
but what when multiplied is 1 and when added is 8
I can't think of anything
4x^2 + 8x + 1 4x^2 + 4x + 4x + 1
why did you do that?
OH I remember!!
ok, cool. ;D
Alright let me try this one :p Um. I rmember what you do kins but not the exact steps
I skippped thorugh this unit and now im paying the price lol. I am a straight A student I just kinda was lazy with note taking, hw, ect and I dont really remember
lol.
4x^2 + 8x + 1 a= 4 b= 8 c = 1 a*c = 4 b = 8 Now we need two terms to which when we multiply we get 4 and when we add we get 8.
wait. i just found out this cannot be factorized. lol @StealerGirly50
okay I cant think of anything. To get four while multiplying you can have 1 and 4 which adds to 5, 2 and 2 which adds to 4
i have taught people from flvs. it's easyyy
we will use Quadratic formula now.
okay whats the formula? I am so mad at myself! ugh! School is so freaking easy and I screwed up just for one unit now I have to relearn everything :/
Here it is, http://2.bp.blogspot.com/_9xX2yNGJA4E/TPm214sFVjI/AAAAAAAAADI/nVLP-mPhYCM/s1600/QuadraticFormula.JPG i helped a girl she failed her algebra 3 times! D: I helped her and she passed. ;D
I tutored people in algebra before beleive it or not. I catch on quick in school but now that i tried online second semester you can kinda skip through everything cause the quzzes are super easy so i kinda slacked lol
that's cool. haha @slacked.
-8+ square root of 8^2-4(4)(1) _______________________________ 2(4)
-8 + square root of 64-16 _______________________________ 8
-8 + sqr root of 48 ______________________ 8
there is no even sqr root of 48 though....
use calc. you will get value in decimals.
okay let me find it real quick
Sure.
-8 +6.928203230275509 _____________________________ 8
you should get, -1.87, -0.13
I didnt lol
what did I do wrong
?
i just checked, you are doing correctly.. must have inserted wrong values in calc.
oh yay your calculator must of rounded cause I got -.1339745962155614
lol, i rounded by myself.
so what do I do after I get the -.13
that's the answer.
how did you figue -1.87?
*figure
umm, we had two equations.
solve another 1.
oh duh sorry im tired lol. ok I got it yayy
Lol, congrats.
I had one more question: Part 1: Solve each of the quadratic equations below. Show your work. (3 points) x2 − 25 = 0 and x2 = 2x + 15 Part 2: Describe what the solution(s) represent to the graph of each. (2 points) Part 3: How are the graphs alike? How are they different? (2 points) (7 points) I solved everything except part 2
How do I do part 2
Use the dicriminant, b^2-4ac to find out.
HOw does that describe what the solutions represent to the graph?
is it's less than zero = imaginary solutions if it's zero = equal solutions if it's greater = two real solutions
okay thanks i pretty much had to relearn everything in this unit before my eoc exam thanks!
Welcome! :D
two real solutions!
cause its 16
Ok, perfect.
thanks bye
:)
Welcome. Byeee.
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