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Mathematics 17 Online
OpenStudy (anonymous):

can anyone answer a question about probability?

jhonyy9 (jhonyy9):

???

OpenStudy (anonymous):

kk what is the probability question

OpenStudy (anonymous):

A committee has 13 members, 5 men and 8 women. 4 members are selected at random to attend a meeting drawn from a hat. What is the probability that all 4 selected are men?

OpenStudy (mertsj):

\[\frac{5}{13}\times\frac{4}{12}\times\frac{3}{11}\times\frac{2}{10}\]

OpenStudy (anonymous):

the number of possible outcomes is 13 and the # of events that occur is 4; so would you divide 4 by 13?

OpenStudy (anonymous):

It's not as plain simple since you have 2 categories to pick from!

OpenStudy (anonymous):

so do you have a simple equation to use with probabilty?

OpenStudy (mertsj):

The number of possible outcomes is only 13 when the first selection is made. You can't select the same person over again so after you select the first person, the number of possible outcomes is 12

OpenStudy (anonymous):

P ( first man) = total men/ total

OpenStudy (mertsj):

I gave you the solution. Cancel the common factors and multiply what is left.

OpenStudy (anonymous):

So the answer would be 69/10000

OpenStudy (mertsj):

So you don't know how to multiply fractions?

OpenStudy (anonymous):

60/4290

OpenStudy (mertsj):

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