Question

Can some please help me check over my work:
9: (7c^7d^2)^-2
10. x^5y^-8/x^5y^-6
11. 12a^-3b^9/21a^2b^-5
12. m^-5n^6p^-4/m^-7np^3

Answer 1

Only if you say what you got can we check the outcome.

Answer 2

9. ?
10: 1/y^2
11. ?
12. n^5/m^2p^7

Answer 3

can you help me with 9 & 11

Answer 4

\[(7c^7d^2)^{-2}=\frac{1}{(7c^7d^2)^2}=\frac{1}{49c ^{14}d ^{4}}\]

Answer 5

\[\frac{12x ^{-3}b^9}{21a^2b ^{-5}}=\frac{12b^9b^5}{21a^2a^3}=\frac{4b ^{14}}{7a^5}\]

Answer 6

10 is correct.

Answer 7

\[\frac{m ^{-5}n^6p ^{-4}}{m ^{-7}np^3}=\frac{m^2n^5}{p^7}\]

Answer 8

That's number 12. You had it right except for the m^2 is on the top.

Answer 9

Oh okay, Thank you so muchh!

Answer 10

yw