Can some please help me check over my work:
9: (7c^7d^2)^-2
10. x^5y^-8/x^5y^-6
11. 12a^-3b^9/21a^2b^-5
12. m^-5n^6p^-4/m^-7np^3

Question

Can some please help me check over my work:
9: (7c^7d^2)^-2
10. x^5y^-8/x^5y^-6
11. 12a^-3b^9/21a^2b^-5
12. m^-5n^6p^-4/m^-7np^3

mertsj · Answer

Only if you say what you got can we check the outcome.

anonymous · Answer

9. ?
10:  1/y^2
11.  ?
12. n^5/m^2p^7

anonymous · Answer

can you help me with 9 & 11

mertsj · Answer

$$(7c^7d^2)^{-2}=\frac{1}{(7c^7d^2)^2}=\frac{1}{49c ^{14}d ^{4}}$$

mertsj · Answer

$$\frac{12x ^{-3}b^9}{21a^2b ^{-5}}=\frac{12b^9b^5}{21a^2a^3}=\frac{4b ^{14}}{7a^5}$$

mertsj · Answer

10 is correct.

mertsj · Answer

$$\frac{m ^{-5}n^6p ^{-4}}{m ^{-7}np^3}=\frac{m^2n^5}{p^7}$$

mertsj · Answer

That's number 12.  You had it right except for the m^2 is on the top.

anonymous · Answer

Oh okay, Thank you so muchh!

mertsj · Answer

yw