When N identical capacitors are connected in series across a battery, the energy stored is U. If the same capacitors were connected in parallel across the same battery, then how much energy would be stored?
NU
N2U
U/N
U

Question

When N identical capacitors are connected in series across a battery, the energy stored is U. If the same capacitors were connected in parallel across the same battery, then how much energy would be stored?
	NU
	N2U
	U/N
	U

mos1635 · Answer

capacitors are connected in series 
same q same V1=V/N 
U1=1/2 C*(V/N)^2
 U(total-1)=N*U1=C*V^2/2N 
capacitors connected in parallel 
same V 
U2=1/2 C*V^2 
U(total-2)=1/2 N*C*V^2

U(total-2)/U(total-1)=
C*V^2/2N/N*C*V^2/2=>U(total-2)=N^2* U(total-1)

anonymous · Answer

$$Ceq=N/C1$$
$$U=1/2.(C1/N).V^{2}$$
$$U'=N.1/2.(C1.V^{2})$$

anonymous · Answer

just divide now

anonymous · Answer

$$U'=N^{2}.U$$