Question

please help me find the vertex and intercepts fory =2x^2-3x+3

Answer 1

x = -b/2a

x = 3/4

plug it in to get y_coordinate
vertex: (3/4, f(3/4))

For intercepts plug in 0 for x,y respectively
y_int = (0,3)

x_int --> 2x^2 -3x +3 = 0
use quadratic formula
x = 3 +-sqrt(9-4(2)(3)) / 4
you get neg inside sqrt, no real solutions

Answer 2

thank you...I didnt know how to begin it ,,,so the vertex is just (3/4)?

Answer 3

is it not -b/2a? or is just b/2a ok?

Answer 4

no it has to be -b/2a
and for the vertex (x,y) there is x_coord and y_coord just like any other point
the formula -b/2a is a shortcut to find the x_coord, but you have to plug it in to the function to get the y_coord

you can also use completing the square to obtain the vertex form, but many students do not like this method hence the shortcut